9.10: Conjugate Carbonyl Additions - The Michael Reaction

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    9.10: Conjugate Carbonyl Additions - The Michael Reaction
    Objectives

    After completing this section, you should be able to

    1. write an equation to illustrate the Michael reaction.
    2. write a detailed mechanism for a given typical Michael reaction.
    3. identify the product formed in a given Michael reaction.
    4. identify the reagents necessary to synthesize a given compound by a Michael reaction.
    Key Terms
    • Michael reaction
    Study Notes

    Before studying this section in detail, you should review conjugate addition to α,β‑unsaturated carbonyl compounds (Section 5.14).

    Notice the wide variety of compounds that can take part in a Michael reaction. As usual, you should not feel overwhelmed by the number of different compounds that can be used, just keep in mind that in all cases the mechanism is essentially the same.

     

    Michael Reaction

    Certain nucleophiles undergo conjugate addition with the alkene of an α, β-unsaturated carbonyl compounds rather than undergo direct nucleophilic addition with the carbonyl. During conjugate addition, a nucleophile adds to the electrophilic β-alkene carbon to form a C-Nuc bond. If the starting materials contain an ester, the corresponding alkoxide is used as the base in the reaction. Otherwise, a hydroxide base, such as sodium or potassium hydroxide, is commonly used.

    The reversible reaction shows a conjugated carbonyl compound reacting with a nucleophile to form an intermediate with a carbanion. Further reaction of intermediate yields a conjugate addition product.
    General Reaction of the Michael Reaction

    When enolate nucleophiles undergo conjugate addition with an α, β-unsaturated carbonyl the process is called a Michael Reaction. The Michael reaction works best with particularly acidic enolate donors such as malonic esters, β-keto esters, etc. Enolates which are weaker acids tend to undergo nucleophilic addition to the carbonyl rather than conjugate addition. For example, malonic ester’s acidic α-hydrogens can be easily deprotonated by sodium ethoxide to form an enolate. The enolate adds to propenal to form the conjugate addition product.

    download-removebg-preview (23).png

    Mechanism of Michael Reaction

    During a Michael reaction, the enolate acts as a nucleophilic donor, and the α, β-unsaturated carbonyl acts as the electrophilic acceptor. The mechanism is a mixture of an alpha-substitution for the enolate and a conjugate addition for the α, β-unsaturated carbonyl.

    Notice that the Michael Reaction does not require the deprotonation of the product to push the reaction toward completion. The reaction is thermodynamically favorable because the C-C bond formed in the product is stronger than the C=C bond in the starting material. This means that, unlike the Claisen condensation, this reaction only requires a catalytic amount of reaction base.

    Step 1: Deprotonation

    The alkoxide base removes an alpha-hydrogen to form an enolate nucleophile.

    Michael Mechanism Step 1.svg

    Step 2: Nucleophilic attack on the carbon β to the carbonyl

    The enolate nucleophile then adds to the electrophilic β-carbon of the α, β-unsaturated carbonyl. Conjugation pushes the C=C pi bond electrons onto the carbonyl oxygen, forming a new enolate enolate.

    Michael Mechanism Step 2.svg

    Step 3: Protonation

    The alkoxide is protonated, forming an enol.

    Michael Mechanism Step 3.svg

    Step 4: Tautomerization

    Tautomerization converts the enol back into a carbonyl, forming the neutral conjugate addition product.

    Michael Mechanism Step 4.svg

    Predicting the Product of a Michael Reaction

    During the reaction the C=C pi bond of the α, β-unsaturated carbonyl is broken. An C-H bond is formed on the carbon in the α-position from the carbonyl. An acidic hydrogen is removed from the nucleophile and then it is used to form a C-C bond with the carbon in the beta position from the carbonyl.

    Reactants to products simplified.svg

    1. In the first step, remove the double bond and add two single bonds
    2. Add hydrogen to the bond adjacent to the carbonyl
    3. Add the nucleophile to the other end of the double bond (remember to remove a hydrogen from the nucleophile)
    Worked Example \(\PageIndex{1}\)

    What would be the product of the following conjugate addition?

    download-removebg-preview (24).png

    Strategy
    1. Break the double bond and add two single bonds
    2. Add a hydrogen to the bond adjacent to the carbonyl
    3. Remove a hydrogen from the nucleophile.
    4. Add the nucleophile to the other end of the double bond.
    Solution

    Michael Worked Example B.svg 

     

    Michael Acceptors and Michael Donors

    The Michael reaction can be performed with a wide variety of α, β-unsaturated carbonyl electrophilic acceptors and enolate donors. Michael acceptors such as α, β-unsaturated ketones, aldehydes, esters, amides, and nitro compounds can all participate in this reaction. Michael donors with particularly acidic α-hydrogens, such as β-diketones, β-keto esters, β-keto nitriles, α-nitro ketones, malonic esters, and nitro compounds can be used.

    Table \(\PageIndex{1}\): Some Michael Acceptors and Michael Donors
    Michael acceptors Michael donors

    CH2=CH-CH=O

    Propenal

    α,β-unsaturated aldehyde

    The structure of beta-diketone, a Michael donor. Carbonyl with substituent R is bonded to C H 2, which is bonded to another carbonyl with substituent R prime. β-Diketone
    The structure of the propenal shows a three-carbon chain. A double bond is shared between the second and third carbon. The first carbon is part of C H O group.

    3-Buten-2-one

    α,β-unsaturated ketone

    The beta-keto ester has a C H 2 group between two carbonyls. An ethoxy group is attached to one terminal carbonyl, and an R group is on the other terminus. β-Keto ester
    The structure of but-3-en-2-one (Michael acceptor) shows a four-carbon chain with a carbonyl at the second carbon. A double bond connects the third and fourth carbon.

    Ethyl propenoate

    α,β-unsaturated ester

    The structure of diethyl malonate, a Michael donor. Carbonyl with ethoxy substituent is bonded to C H 2, which is bonded to another carbonyl with ethoxy substituent. Diethyl malonate
    The structure of ethyl propenoate (Michael acceptor) shows a three-carbon chain where the second and third carbon share double bond. An ethoxy group is attached to the first carbonyl carbon.

    Propenamide

    α,β-unsaturated amide

    The structure of beta-keto nitrile, Michael donor. R is bonded to the carbonyl group which is further bonded to methylene. Methylene is bonded with a cyanide group. β-Keto nitrile
    The structure of propenenitrile (acrylonitrile) shows a three-carbon chain where the first carbon is triple-bonded to nitrogen. A double bond is shared between the second and third carbon atoms.

    Propenenitrile

    α,β-unsaturated nitrile

    The structure of a nitro compound, Michael-donor. R group is single-bonded to methylene which is further linked to the nitro group. Nitro compound
    The structure of nitroethylene (Michael acceptor) shows a two-carbon chain. N O 2 group is attached to the first carbon. The first and second carbon atoms are double-bonded. Nitroethylene    


     

    Stereochemical Consideration of Micheal Reactions

    During a Michael reaction, two sp2 hybridized carbons are converted to sp3 hybridization. Both of them have the possibility of creating a chiral carbon. Michael reactions are often performed using an α, β-unsaturated carbonyl with only hydrogen substituents on the alkene to prevent the formation of chiral carbons. If either carbon in the alkene has an alkyl substituent it will likely form a chiral carbon in the Michael reaction product. The α-carbon of the enolate donor also has the possibility of forming a chiral carbon as discussed in Section 9-7.

    download-removebg-preview (22).png

     

    Planning a Synthesis Using a Michael Reaction

    The true utility of the Michael reaction is seen when considering it use in a synthesis. The reaction can be used to prepare aldehydes, ketones, esters, amides, nitriles, and nitro compounds. A target molecule can possibly be made using a Michael reaction if it contains one of these functional groups and an alkyl chain at least three carbons long. The key bond cleavage is a C-C bond between β and gamma carbons from a carbonyl-like group. The fragment with the Y group loses an α-hydrogen and then forms a C=C bond between the α and beta carbon. The carbon of the other fragment gains a hydrogen. This fragment should possess an acidic α-hydrogen and should be made up of Michael donor fragments such as those listed in Table \(\PageIndex{1}\). In some cases, there may be more than one fragmentation variation. Each variation should be investigated and the possible starting materials compared for viability.

    download-removebg-preview (21).png

    Worked Example \(\PageIndex{2}\): Using the Michael Reaction

    How might you obtain the following compound using a Michael reaction?

    The structure shows a cyclohexanone ring connected to C O O E t and C H 2 C H 2 C O O E t groups at the first carbon.
    Strategy

    A Michael reaction involves the conjugate addition of a stable enolate ion donor to an α,β-unsaturated carbonyl acceptor, yielding a 1,5-dicarbonyl product. Usually, the stable enolate ion is derived from a β-diketone, β-keto ester, malonic ester, or similar compound. The C–C bond formed in the conjugate addition step is the one between the α carbon of the acidic donor and the β carbon of the unsaturated acceptor.

    Solution
    The reaction between ethyl-2-oxocyclohexanecarboxylate with alpha, beta-unsaturated ester (three-carbon) in the presence of sodium ethoxide in ethanol gives ethyl-1-(3-ethoxy-3-oxopropyl)-2-oxocyclohexanecarboxylate (1,5-dicarbonyl compound) with a new carbon-carbon bond between cyclohexane and ester.
    Worked Example \(\PageIndex{3}\): Using the Michael Reaction

    How could the following molecule be synthesized using a Michael Reaction?

    download-removebg-preview (20).png

    Strategy

    Pathway 1

    Michael Worked Example 2 B.svg

    Starting Materials 1

    download-removebg-preview (17).png

    Pathway 2

    Michael Worked Example 2 D.svg

    Starting Material 2

    download-removebg-preview (18).png

    Solution

    When comparing the two sets of possible starting materials pathway 1 is preferred. The Michael enolate donor is particularly acidic because its conjugate base is stabilized by two carbonyls. The Michael enolate donor for pathway 2 does not have the same acidity. Consequently, the enolate would preferably undergo nucleophilic addition rather than conjugate addition. This makes the starting materials of pathway 1 preferred for synthesizing the starting material.

    download-removebg-preview (19).png

    In combination with alkylations and condensations, the Michael reaction may be used to construct a wide variety of complex molecules from relatively simple starting materials. The carbon nucleophiles used in the following examples include cyanide ion, sodium diethylmalonate and the conjugate base of cyclohexane-1,3-dione. These anions are sufficiently stable that their addition reactions may be presumed reversible. If this is so, the thermodynamic argument used for hetero-nucleophile additions would apply here as well, and would indicate preferential formation of 1,4-addition products. Cyanide addition does not always follow this rule, and aldehydes often give 1,2-products (cyanohydrins). In each case the initial reaction is a Michael addition, and the new carbon-carbon bond is colored magenta. Any subsequent bonds that are formed by other reactions are colored orange.

    Illustration

    Illustration

    Exercise \(\PageIndex{1}\)

    What product would you obtain from a base-catalyzed Michael reaction of 2,4-pentanedione with each of the following α,β-unsaturated acceptors?

    1. 2-Cyclohexenone
    2. Propenenitrile
    3. Ethyl 2-butenoate
    Answer
    a. 3-(3-oxocyclohexyl)pentane 2,4 dione structure shows a cyclohexanone bonded to C H (C O C H 3)2 group at the first carbon.     b. A four-carbon chain in which C 1 is part of a cyano group, with two acetyl groups (C H 3 C O) on C 4.     c. A four-carbon chain with an ethyl ester on C 1, methyl on C 3, and two acetyl groups (C H 3 C O) on C 4.
    Exercise \(\PageIndex{2}\)

    What product would you obtain from a base-catalyzed Michael reaction of 3-buten-2-one with each of the following nucleophilic donors?

    1. Structure of diethyl malonate, a 3-carbon chain with ethy esters on the terminal carbons.      b. Structure of cyclopentanone with C O O E t on C 2.
    Answer
    1. Structure of a five-carbon chain with an oxo group on C 2 and two Et O 2 C groups on C 5      b.Structure of cyclopentanone ring with the substituents C O O E t and C H 2 C H 2 C double-bonded O C H 3 on C 2.
    Exercise \(\PageIndex{3}\)

    What would be the starting materials required to make the following molecules using a Michael reaction? Red = Oxygen, Grey = Carbon, White = Hydrogen, Blue = Nitrogen.

    a. clipboard_e86aaa986d5d7204670d9936d01398e56.png   b. The ball-and-stick model shows a seven-carbon chain with N O 2 on sixth and carbonyl on third carbons. Gray, white, red, and blue spheres denote carbon, hydrogen, oxygen, and nitrogen.

    Answers

    a. download-removebg-preview (25).png    b. CH3CH2COCH═CH2 + CH3CH2NO2


    This page titled 9.10: Conjugate Carbonyl Additions - The Michael Reaction was last modified on Tue, 18 Mar 2025 01:10:58 GMT and is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Sol Parajon Puenzo (Cañada College) .