Opening the book…
1. (a)
\[
\begin{array}{ccc}
\operatorname{AgI}(s) \rightleftharpoons & \operatorname{Ag}^{+}(a q)+ & \mathrm{I}^{-}(a q) \\
& x & \underline{x}
\end{array}
\notag \]
(b)
\[
\mathrm{CaCO}_3(s) \rightleftharpoons \begin{array}{ccc}
& \mathrm{Ca}^{2+}(a q)+ & \mathrm{CO}_3^{2-}(a q) \\
& \underline{x} & x
\end{array}
\notag \]
(c)
\[
\begin{array}{ll}
\mathrm{Mg}(\mathrm{OH})_2(s) \rightleftharpoons & \mathrm{Mg}^{2+}(a q) \\
& x
\end{array}+2 \mathrm{OH}^{-}(a q) ~ 2 x .
\notag \]
(d)
\[
\mathrm{Mg}_3\left(\mathrm{PO}_4\right)_2(s) \rightleftharpoons 3 \mathrm{Mg}^{2+}(a q)+2 \mathrm{PO}_4^{3-}(a q)
\notag \]
(e)
\[
\begin{array}{cccc}
\mathrm{Ca}_5\left(\mathrm{PO}_4\right)_3 \mathrm{OH}(s) \rightleftharpoons & 5 \mathrm{Ca}^{2+}(a q)+ & 3 \mathrm{PO}_4^{3-}(a q)+ & \mathrm{OH}^{-}(a q) \\
\underline{5 x} & \underline{3 x} & x
\end{array}
\notag \]
3. There is no change. A solid has an activity of 1 whether there is a little or a lot.
5. The solubility of silver bromide at the new temperature must be known. Normally the solubility increases and some of the solid silver bromide will dissolve.
7. \(\mathrm{CaF}_2, \mathrm{MnCO}_3\), and ZnS
9. (a) \(\mathrm{LaF}_3(s) \rightleftharpoons \mathrm{La}^{3+}(a q)+3 \mathrm{~F}^{-}(a q)\)
\[
\begin{aligned}
& K_{\mathrm{sp}}=\left[\mathrm{La}^{3+}\right]\left[\mathrm{F}^{-}\right]^3 ; \\
& K_{\mathrm{sp}}=\left[\mathrm{Ca}^{2+}\right]\left[\mathrm{CO}_3{ }^{2-}\right] ; \\
& K_{\mathrm{sp}}=\left[\mathrm{Ag}^{+}\right]^2\left[\mathrm{SO}_4{ }^{2-}\right] ; \\
& K_{\mathrm{sp}}=\left[\mathrm{Pb}^{2+}\right]\left[\mathrm{OH}^{-}\right]^2
\end{aligned}
\notag \]
11. (a) \(1.77 \times 10^{-7}\); (b) \(1.6 \times 10^{-6}\); (c) \(2.2 \times 10^{-9}\); (d) \(7.91 \times 10^{-22}\)
13. (a) \(2 \times 10^{-2} M\); (b) \(1.5 \times 10^{-3} M\); (c) \(2.27 \times 10^{-9} M\); (d) \(2.2 \times 10^{-10} M\)
15. (a) \(6.4 \times 10^{-9} M=\left[\mathrm{Ag}^{+}\right],\left[\mathrm{Cl}^{-}\right]=0.025 M\). Check: \(\dfrac{6.4 \times 10^{-9} M}{0.025 M} \times 100 \%=2.6 \times 10^{-5} \%\),an insignificant change;
(b) \(2.2 \times 10^{-5} M=\left[\mathrm{Ca}^{2+}\right],\left[\mathrm{F}^{-}\right]=0.0013 M\). Check: \(\dfrac{2.26 \times 10^{-5} M}{0.00133 M} \times 100 \%=1.70 \%\). This value is less than 5\% and can be ignored.
(c) \(0.2238 M=\left[\mathrm{SO}_4{ }^{2-}\right]\); \(\left[\mathrm{Ag}^{+}\right]=7.4 \times 10^{-3} M\). Check: \(\dfrac{3.7 \times 10^{-3}}{0.2238} \times 100 \%=1.64 \times 10^{-2}\); the condition is satisfied.
(d) \(\left[\mathrm{OH}^{-}\right]=2.8 \times 10^{-3} M ; 5.7 \times 10^{-12} M=\left[\mathrm{Zn}^{2+}\right]\). Check: \(\dfrac{5.7 \times 10^{-12}}{2.8 \times 10^{-3}} \times 100 \%=2.0 \times 10^{-7} \% ; x\) is less than \(5 \%\) of \(\left[\mathrm{OH}^{-}\right]\)and is, therefore, negligible.
17. (a) The change in initial concentration of common ion may not be neglected (must solve quadratic equation)
\[
\begin{aligned}
& {\left[\mathrm{Ti}^{+}\right]=0.031 \mathrm{M}} \\
& {\left[\mathrm{Cl}^{-}\right]=0.0056 \mathrm{M}(\mathrm{~b}) \mathrm{Th}} \\
& {\left[\mathrm{Ba}^{2+}\right]=2.4 \times 10^{-4} \mathrm{M}} \\
& {\left[\mathrm{~F}^{-}\right]=0.313 \mathrm{M} ;}
\end{aligned}
\notag \]
(c) The change in initial concentration of common ion may be neglected.
\[
\begin{aligned}
& {\left[\mathrm{Mg}^{2+}\right]=0.0244 \mathrm{M}} \\
& {\left[\mathrm{C}_2 \mathrm{O}_4{ }^{2-}\right]=2.9 \times 10^{-5} M}
\end{aligned}
\notag \]
(d) The change in initial concentration of common ion may be neglected.
\[
\begin{aligned}
& {\left[\mathrm{Ca}^{2+}\right]=5.18 \times 10^{-4} \mathrm{M}} \\
& \left.\left[\mathrm{C}_2\right)_4{ }^{2-}\right]=0.051 \mathrm{M}
\end{aligned}
\notag \]
19. The changes in concentration are greater than 5\% and thus exceed the maximum value for disregarding the change.
21. \(\mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}\) is the most soluble Ca salt in mol/L, and it is also the most soluble Ca salt in g/L.
23. \(7.8 \times 10^{-3} M=\left[\mathrm{SO}_4{ }^{2-}\right]=\left[\mathrm{Ca}^{2+}\right]\); Since this concentration is higher than \(2.60 \times 10^{-3} M\), "gyp" water does not meet the standards.
25. Mass \(\left(\mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}\right)=0.72 \mathrm{~g}\)
27. (a) \(\left[\mathrm{Ag}^{+}\right]=\left[\mathrm{l}^{-}\right]=1.3 \times 10^{-5} M\); (b) \(\left[\mathrm{Ag}^{+}\right]=2.88 \times 10^{-2} M\), \(\left[\mathrm{SO}_4{ }^{2-}\right]=1.44 \times 10^{-2} M\); (c) \(\left[\mathrm{Mn}^{2+}\right]=3.7 \times 10^{-5} M\), \(\left[\mathrm{OH}^{-}\right]=7.4 \times 10^{-5} M\); (d) \(\left[\mathrm{Sr}^{2+}\right]=4.3 \times 10^{-2} M,\left[\mathrm{OH}^{-}\right]=8.6 \times 10^{-2} M\); (e) \(\left[\mathrm{Mg}^{2+}\right]=1.3 \times 10^{-4} M\), \(\left[\mathrm{OH}^{-}\right]=2.6\) \(\times 10^{-4} M\).
29. (a) \(1.45 \times 10^{-4}\); (b) \(8.2 \times 10^{-55}\); (c) \(1.35 \times 10^{-4}\); (d) \(1.18 \times 10^{-5}\); (e) \(1.08 \times 10^{-10}\)
31. (a) \(\mathrm{CaCO}_3\) does precipitate. (b) The compound does not precipitate. (c) The compound does not precipitate. (d) The compound precipitates.
33. \(1.42 \times 10^{-9} M\)
35. \(9.2 \times 10^{-13} M\)
37. \(\left[\mathrm{Ag}^{+}\right]=1.8 \times 10^{-3} \mathrm{M}\)
39. \(6.3 \times 10^{-4}\)
41. (a) 2.25 L ; (b) \(7.2 \times 10^{-7} \mathrm{~g}\)
43. 100\% of it is dissolved
45. (a) \(\mathrm{Hg}_2{ }^{2+}\) and \(\mathrm{Cu}^{2+}\) : Add \(\mathrm{SO}_4{ }^{2-}\). (b) \(\mathrm{SO}_4{ }^{2-}\) and \(\mathrm{Cl}^{-}\): Add \(\mathrm{Ba}^{2+}\). (c) \(\mathrm{Hg}^{2+}\) and \(\mathrm{Co}^{2+}\) : Add \(\mathrm{S}^{2-}\). (d) \(\mathrm{Zn}^{2+}\) and \(\mathrm{Sr}^{2+}\) : Add \(\mathrm{OH}^{-}\)until \(\left[\mathrm{OH}^{-}\right]=0.050 \mathrm{M}\). (e) \(\mathrm{Ba}^{2+}\) and \(\mathrm{Mg}^{2+}\) : Add \(\mathrm{SO}_4{ }^{2-}\). (f) \(\mathrm{CO}_3{ }^{2-}\) and \(\mathrm{OH}^{-}:\)Add \(\mathrm{Ba}^{2+}\).
47. Agl will precipitate first.
49. \(1.5 \times 10^{-12} M\)
51. 3.99 kg
53. (a) \(3.1 \times 10^{-11}\); (b) \(\left[\mathrm{Cu}^{2+}\right]=2.6 \times 10^{-3}\); \(\left[\mathrm{IO}_3{ }^{-}\right]=5.3 \times 10^{-3}\)
55. \(9.3 \times 10^{-6} \mathrm{~g} \mathrm{~Pb}(\mathrm{OH})_2\)
57. \(\mathrm{Mg}(\mathrm{OH})_2(s) \rightleftharpoons \mathrm{Mg}^{2+}+2 \mathrm{OH}^{-}\) \(K_{\mathrm{sp}}=\left[\mathrm{Mg}^{2+}\right]\left[\mathrm{OH}^{-}\right]^2\) \(1.23 \times 10^{-3} \mathrm{~g} \mathrm{Mg}(\mathrm{OH})_2\)
59. \(\mathrm{MnCO}_3\) will form first since it has the smallest \(K_{\mathrm{sp}}\) value among these homologous compounds and is therefore the least soluble. \(\mathrm{MgCO}_3 \bullet 3 \mathrm{H}_2 \mathrm{O}\) will be the last to precipitate since it has the largest K_sp value and is the most soluble. \(K_{\mathrm{sp}}\) value.
62. when the amount of solid is so small that a saturated solution is not produced
64. \(8.2 \times 10^{-5} M\)
66. \(5 \times 10^{23}\)
68.
\[\left[\mathrm{Cd}^{2+}\right]=5.0 \times 10^{-5} M ;\left[\mathrm{CN}^{-}\right]=2.0 \times 10^{-4} M\notag \]
70. \(\left[\mathrm{Co}^{3+}\right]=3.0 \times 10^{-6} M ;\left[\mathrm{NH}_3\right]=1.8 \times 10^{-5} M\)
72. 1.3 g
74. 0.79 g
76. (a)
(b)
(c)
(d)
(e)
78. (a)
(b)\(\mathrm{H}_3 \mathrm{O}^{+}+\mathrm{CH}_3{ }^{-} \longrightarrow \mathrm{CH}_4+\mathrm{H}_2 \mathrm{O}\)
(c) \(\mathrm{CaO}+\mathrm{SO}_3 \longrightarrow \mathrm{CaSO} 4\)
(d) \(\mathrm{NH}_4^{+}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{O}^{-} \longrightarrow \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{NH}_3\)
80. 0.0281 g
82. HNO3(𝑙)+HF(𝑙)⟶H2NO3++F−; HF(𝑙)+BF3(𝑔)⟶H++BF4
84. (a) H3BO3+H2O⟶H4BO4−+H+; (b) The electronic and molecular shapes are the same—both tetrahedral. (c) The tetrahedral structure is consistent with sp3 hybridization.
86. 0.014 M
88. 7.2 × 10–15 M
90. 4.4 × 10−22 M
93. [OH−] = 4.5 × 10−6; [Al3+] = 2 × 10–16 (molar solubility)
95. Ksp=[Ba2+][SO42−]=[Ba2+](0.049)=1.08×10–10[Ba2+]=2.2×10–9; (molar solubility)
97. [OH–] = 7.6 × 10−3 M; [Pb2+] = 2.1 × 10–11 (molar solubility)
99. 7.66
101. (a) Ksp = [Mg2+][F–]2 = (1.21 × 10–3)(2 × 1.21 × 10–3)2 = 7.09 × 10–9
(b) 7.09 × 10–7 M
(c) Determine the concentration of Mg2+ and F– that will be present in the final volume. Compare the value of the ion product [Mg2+][F–]2 with Ksp. If this value is larger than Ksp, precipitation will occur.
0.1000 L × 3.00 × 10–3 M Mg(NO3)2 = 0.3000 L × M Mg(NO3)2
M Mg(NO3)2 = 1.00 × 10–3 M
0.2000 L × 2.00 × 10–3 M NaF = 0.3000 L × M NaF
M NaF = 1.33 × 10–3 M
ion product = (1.00 × 10–3)(1.33 × 10–3)2 = 1.77 × 10–9 This value is smaller than Ksp, so no precipitation will occur.
(d) MgF2 is less soluble at 27 °C than at 18 °C. Because added heat acts like an added reagent, when it appears on the product side, the Le Châtelier’s principle states that the equilibrium will shift to the reactants’ side to counter the stress. Consequently, less reagent will dissolve. This situation is found in our case. Therefore, the reaction is exothermic.
103. BaF2, Ca3(PO4)2, ZnS; each is a salt of a weak acid, and the [H3O+] from perchloric acid reduces the equilibrium concentration of the anion, thereby increasing the concentration of the cations
105. Effect on amount of solid CaHPO4, [Ca2+], [OH–]: (a) increase, increase, decrease; (b) decrease, increase, decrease; (c) no effect, no effect, no effect; (d) decrease, increase, decrease; (e) increase, no effect, no effect
22.14.15: Chapter 15 is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.
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