5.2.H: Homework

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    5.2.H: Homework

    Practice Makes Perfect

    Find the Greatest Common Factor (GCF) of Two or More Expressions

    In the following exercises, find the greatest common factor.

    1. \(10p^3,12p\)

    Answer

    \(2p\)

    2. \(12m^2n^3,30m^5n^3\)

    Answer

    \(6m^2n^3\)

    Factor the Greatest Common Factor from a Polynomial

    In the following exercises, factor the greatest common factor from each polynomial.

    3. \(6m+9\)

    Answer

    \(3(2m+3)\)

    4. \(9n−63\)

    Answer

    \(9(n−7)\)

    5. \(3x^2+6x−9\)

    Answer

    \(3(x^2+2x−3)\)

    6. \(8y^3+16y^2\)

    Answer

    \(8y^2(y+2)\)

    7. \(5x^3−15x^2+20x\)

    Answer

    \(5x(x^2−3x+4)\)

    8. \(12xy^2+18x^2y^2−30y^3\)

    Answer

    \(6y^2(2x+3x^2−5y)\)

    9. \(20x^3y−4x^2y^2+12xy^3\)

    Answer

    \(4xy(5x^2−xy+3y^2)\))

    10. \(−2x−4\)

    Answer

    \(−2(x+4)\)

    11. \(−4p^3q−12p^2q^2+16pq^2\)

    Answer

    \(−4pq(p^2+3pq−4q)\)

    12. \(5x(x+1)+3(x+1)\)

    Answer

    \((x+1)(5x+3)\)

    Factor Differences of Squares

    In the following exercises, factor.

    Exercise 13

    \(x^2−16\)

    Answer

    \((x−4)(x+4)\)

    Exercise 14

    \(25v^2−1\)

    Answer

    \((5v−1)(5v+1)\)

    Exercise 15

    \(121x^2−144y^2\)

    Answer

    \((11x−12y)(11x+12y)\)

    Exercise 16

    \(169c^2−36d^2\)

    Answer

    \((13c−6d)(13c+6d)\)

    Exercise 17

    \(4−49x^2\)

    Answer

    \((2−7x)(2+7x)\)

    Exercise 18

    \(16z^4−1\)

    Answer

    \((2z−1)(2z+1)(4z^2+1)\)

    Exercise 19

    \(5q^2−45\)

    Answer

    \(5(q−3)(q+3)\)

    Exercise 20

    \(24p^2+54\)

    Answer

    \(6(4p^2+9)\)

    Applications

    Solve the following.

    Exercise 21

    The surface area of a right cylinder is given by the formula \(A=2\pi rh+2\pi r^2\) where \(r\) is the radius of the base and \(h\) is the height of the cylinder. Factor the right hand side of this equation.

    Answer

    \[A=2\pi r(h+r)\]

    Exercise 22

    In Einstein's theory of special relativity, the total energy of an object (\(E\)) considers both its momentum (\(p\)) and its rest-mass energy (\(mc^{2}\)). The relationship can be given by the formula

    \(E^2 − (pc)^2 = (mc^2)^2\)

    where \(c\) is the speed of light constant.

    Factor the left-hand side of this equation.

    Answer

    \((E+pc)(E−pc)\)


    This page titled 5.2.H: Homework was last modified on Mon, 06 Jul 2026 03:20:44 GMT and is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by Kiersten Purves.