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Let \(A = \begin{bmatrix} 3 & 1 \\ -1 & 3 \end{bmatrix}\). Find the Singular Value Decomposition (SVD) of \( A \).
- Answer
-
\(
U = \begin{bmatrix} \frac{1}{\sqrt{10}} & \frac{3}{\sqrt{10}} \\ \frac{3}{\sqrt{10}} & -\frac{1}{\sqrt{10}} \end{bmatrix}, \quad
\Sigma = \begin{bmatrix} \sqrt{10} & 0 \\ 0 & \sqrt{10} \end{bmatrix}, \quad
V = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}
\)
Let \(A=\left[\begin{array}{rrr} 4 & 0 \\ 3 &-5 \end{array}\right]\). Find the Singular Value Decomposition (SVD) of \(A\).
Let \( A = \begin{bmatrix} 3 & 1 & 1 \\ -1 & 3 & 1 \end{bmatrix}\). Find the Singular Value Decomposition (SVD) of \( A \).
- Answer
-
\(U = \begin{bmatrix}
\frac{1}{\sqrt{2}} & -\frac{1}{\sqrt{2}} \\
\frac{1}{\sqrt{2}} & \frac{1}{\sqrt{2}}
\end{bmatrix}, \quad
\Sigma = \begin{bmatrix}
2\sqrt{3} & 0 & 0 \\
0 & \sqrt{10} & 0
\end{bmatrix}, \quad
V^T = \begin{bmatrix}
\frac{1}{\sqrt{6}} & -\frac{2}{\sqrt{5}} & -\frac{1}{\sqrt{30}} \\
\sqrt{\frac{2}{5}} & \frac{1}{\sqrt{5}} & -\sqrt{\frac{2}{5}} \\
\frac{1}{\sqrt{6}} & 0 & \sqrt{\frac{5}{6}}
\end{bmatrix}\)
Let \(A=\left[\begin{array}{rrr} 2 & -2 & 1 \\ 4 & -8 &-8 \end{array}\right]\). Find the Singular Value Decomposition (SVD) of \(A\).
Let \(A\) be an \(n\times n\) matrix with rank n. Show the absolute value of det(A) equals the product of its singular values.
This page titled 6.8E: Exercises for Section 6.8 was last modified on Thu, 10 Apr 2025 05:36:09 GMT and is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by Doli Bambhania, Fatemeh Yarahmadi, and Bill Wilson.
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