Opening the book…
Reading Questions
- What is the primary purpose of the Power Reduction Identities?
- From which identities are the Power Reduction Identities derived?
- What is the Power Reduction Identity for \(\sin^2(\theta)\)?
- How are the Half-Angle Identities derived from the Power Reduction Identities?
- What is the Half-Angle Identity for \(\cos(\frac{\theta}{2})\)?
- What does the \(\pm\) symbol in the Half-Angle Identities signify?
- How do you determine whether to use the positive or negative root when applying a Half-Angle Identity?
- If \(\theta\) is in Quadrant IV, in which quadrant must \(\frac{\theta}{2}\) lie?
- How can you use the Half-Angle Identities to help graph a function like \(y = 3\sin^2(\frac{x}{2})\)?
- To find the exact value of \(\sin(15^\circ)\) using a Half-Angle Identity, what angle would you use for \(\theta\)?
Homework
Basic Skills
For the following exercises, rewrite the expression without exponents.
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\(\cos ^{2} (5x)\)
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\(\cos ^{2} (6x)\)
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\(\sin ^{4} (8x)\)
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\(\sin ^{4} \left(3x\right)\)
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\(\cos ^{2} (x)\sin ^{4} (x)\)
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\(\cos ^{4} (x)\sin ^{2} (x)\)
For the following exercises, use the Half-Angle Identities to find the exact value.
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\(\cos(75^{\circ})\)
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\(\sin(105^{\circ})\)
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\(\cos(67.5^{\circ})\)
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\(\sin(157.5^{\circ})\)
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\(\tan(112.5^{\circ})\)
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\(\cos\left( \dfrac{7\pi}{12} \right)\)
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\(\sin\left( \dfrac{\pi}{12} \right)\)
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\( \sin\left( \dfrac{\pi}{24} \right) \)
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\( \cos\left( \dfrac{\pi}{24} \right) \)
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\( \sin\left( \dfrac{9\pi}{8} \right) \)
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\( \tan\left( \dfrac{3\pi}{8} \right) \)
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\(\cos \left( \dfrac{\pi}{8} \right)\)
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\(\sin \left( \dfrac{5\pi}{8} \right)\)
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\(\tan \left( \dfrac{7\pi}{8} \right)\)
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\( \sin\left( -\dfrac{\pi}{8} \right) \)
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\( \sin\left( \dfrac{13\pi}{24} \right) \)
For the following exercises, use the given information about \(\theta\) to find the exact values of
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\(\sin\left(\dfrac{\theta}{2}\right)\)
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\(\cos\left(\dfrac{\theta}{2}\right)\)
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\(\tan\left(\dfrac{\theta}{2}\right)\)
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\(\sin(\theta) = -\dfrac{7}{25}\) where \(\dfrac{3\pi}{2} < \theta < 2\pi\)
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\(\cos(\theta) = \dfrac{28}{53}\) where \(0 < \theta < \dfrac{\pi}{2}\)
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\(\tan(\theta) = \dfrac{12}{5}\) where \(\pi < \theta < \dfrac{3\pi}{2}\)
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\(\csc(\theta) = 4\) where \(\dfrac{\pi}{2} < \theta < \pi\)
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\(\cos(\theta) = \dfrac{3}{5}\) where \(0 < \theta < \dfrac{\pi}{2}\)
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\(\sin(\theta) = -\dfrac{4}{5}\) where \(\pi < \theta < \dfrac{3\pi}{2}\)
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\(\cos(\theta) = \dfrac{12}{13}\) where \(\dfrac{3\pi}{2} < \theta < 2\pi\)
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\(\sin(\theta) = \dfrac{5}{13}\) where \(\dfrac{\pi}{2} < \theta < \pi\)
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\(\sec(\theta) = \sqrt{5}\) where \(\dfrac{3\pi}{2} < \theta < 2\pi\)
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\(\tan(\theta) = -2\) where \(\dfrac{\pi}{2} < \theta < \pi\)
Synthesis Problems
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Let \(\theta\) be a Quadrant III angle with \(\cos(\theta) = -\dfrac{1}{5}\). Show that this is not enough information to determine the sign of \(\sin\left(\dfrac{\theta}{2}\right)\) by first assuming \(3\pi < \theta < \dfrac{7\pi}{2}\) and then assuming \(\pi < \theta < \dfrac{3\pi}{2}\) and computing \(\sin\left(\dfrac{\theta}{2}\right)\) in both cases.
For the following exercises, graph two cycles of the function.
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\( y = 8 \sin^2\left( \dfrac{x}{2} \right) \)
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\( y = 2 \cos^2\left( \dfrac{x}{2} \right) \)
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\( y = -2 \cos^2\left( \dfrac{x}{2} \right) + 4 \)
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\( y = \dfrac{1}{3} \cos^2\left( \dfrac{x}{2} \right) - \dfrac{1}{6}\)
Proofs
For the following exercises, prove the identity.
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\( \tan\left( \dfrac{1}{2} \theta \right) = \csc\left( \theta \right) - \cot\left( \theta \right)\)
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\( \tan^2\left( \dfrac{1}{2} \theta \right) = \dfrac{\tan\left( \theta \right) - \sin\left( \theta \right)}{\tan\left( \theta \right) + \sin\left( \theta \right)} \)
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\( \sin^2\left( \dfrac{\theta}{2} \right) = \dfrac{\csc\left( \theta \right) - \cot\left( \theta \right)}{2\csc\left( \theta \right)} \)
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\( 2 \sin^2\left( \dfrac{\theta}{2} \right) = \dfrac{\sin^2\left( \theta \right)}{1 + \cos\left( \theta \right)} \)
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\( 2\cos^2\left( \dfrac{\theta}{2} \right) = \dfrac{\sin^2\left( \theta \right)}{1 - \cos\left( \theta \right)} \)
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\( \cos^2\left( \dfrac{\theta}{2} \right) = \dfrac{\tan\left( \theta \right) + \sin\left( \theta \right)}{2 \tan\left( \theta \right)} \)
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\( \sec^2\left( \dfrac{\theta}{2} \right) = \dfrac{2 \sec\left( \theta \right)}{\sec\left( \theta \right) + 1}\)
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\( \csc^2\left( \dfrac{\theta}{2} \right) = \dfrac{2\sec\left( \theta \right)}{\sec\left( \theta \right) - 1} \)
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\( 4 \sin^4\left( \theta \right) = 1 - 2 \cos\left( 2\theta \right) + \cos^2\left( 2\theta \right) \)
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\( \cos^4\left( \theta \right) = \dfrac{1}{4} + \dfrac{\cos\left( 2\theta \right)}{2} + \dfrac{\cos^2\left( 2\theta \right)}{4} \)
Challenge Questions
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Without using your calculator, show that \(\dfrac{\sqrt{2 + \sqrt{3}}}{2} = \dfrac{\sqrt{6} + \sqrt{2}}{4}\)
This page titled 6.4.2: Homework was last modified on Fri, 04 Jul 2025 22:31:39 GMT and is shared under a not declared license and was authored, remixed, and/or curated by Roy Simpson.
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