# Already Gone || COMPLETE Leafpool & Crowfeather MAP

The story of Leafpool and Crowfeather's romance... told with a western-themed twist. --- Note from Fennelfawn: Wow. Writing this description feels so surreal to me. This MAP was quite literally the start of my YouTube journey - it's the very first MAP I joined (in fact, it's the project that finally got me to post my examples and join the animation community!) Releasing this project as the new host - over four years after the original MAP call was posted on May 8, 2021 - makes me so proud of my younger and current selves alike. I was an awkward, shy middle schooler who had no idea what I wanted to do with my life when I joined this MAP. Now I'm in university, getting a degree in chemical engineering. This project has really grown with me and my art journey. You may notice that I had a hand in eleven of the twenty-six parts (a testament to my "screw it, I'll do it myself" attitude.) Part 6 was done over two years ago, while Part 23 was completed just last week. Meanwhile, Part 10 (the very first part I picked up) was redone twice. You can definitely see the differences in styles! I've come such a long way and this project is a major milestone in my art journey. --- Note from pokefan1241: WOW!! 4 years huh, crazy to see this map fully realized! I could not be more proud of all the participants and thankful that this project was picked up by such a passionate new host :) I'm so happy that everyone's hard work finally gets to be shown off! Please give the participants and host…

- Kind: Cartoon
- Year: 2025
- By: Fennelfawn
- Genres: Animation
- Archive: [Internet Archive](https://archive.org/details/already-gone-complete-leafpool-crowfeather-map-uv-4-she-eehtk)
- Licence or status: none stated by the archive
- Who can watch: Tweens profiles and older (the archive gives no rating; placed by Invisible Network from its collection and subjects)

[Watch now](https://invisiblenetwork.ai/watch/archive/ia/already-gone-complete-leafpool-crowfeather-map-uv-4-she-eehtk?play=1)